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\documentclass[a4paper]{article}
\usepackage{graphicx}
\usepackage{tabularx}
\usepackage{enumitem}
\usepackage{chngpage}
\usepackage{calc}
\usepackage[hidelinks]{hyperref}
\usepackage[english]{babel}
\usepackage{fancyvrb}
\usepackage{tikz}
\usepackage{forest}
\usepackage[utf8]{inputenc}
\usepackage{commath}
\usepackage{minted}
\usepackage{quotes}
\usepackage{listings}
\usepackage{graphicx}
\usepackage{minted}
\def\infinity{\rotatebox{90}{8}}
\usepackage[shortlabels]{enumitem}
\usepackage{caption}
\usepackage{float}
\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{diagbox}
\usepackage{slashbox}
\usepackage{geometry} % For page dimensions and margins
\geometry{
paper=a4paper,
top=2.5cm, % Top margin
bottom=3cm, % Bottom margin
left=2cm, % Left margin
right=2cm, % Right margin
}
\usepackage{pgfplots}
\pgfplotsset{width=15cm, height=10cm}
\setminted{
autogobble
}
\begin{document}
\begin{titlepage}
\scshape
\centering
\includegraphics[width=3cm, keepaspectratio]{logo_usi.png}
\par
\vspace{0.1cm}
\texttt{FACULTY OF INFORMATICS}
\vspace{1cm}
\raisebox{-\baselineskip}{\rule{\textwidth}{1px}}
\rule{\textwidth}{1px}
\vspace{0.2cm}
{\LARGE{{Advanced java programming}}}\par \vspace{0.1cm}
Assignment 4
\rule{\textwidth}{2px}
\vspace{1cm}
\begin{tabular}{lp{1cm}l}
Author & \rule{0pt}{3ex} & FEDERICO \mbox{LAGRASTA}\\
&&\\
& \rule{0pt}{3ex} & CLAUDIO \mbox{MAGGIONI}
\end{tabular}
\vspace{1.3cm}
\vfill
\today
\end{titlepage}
\section*{Exercise A: Concurrency}
As no synchronization between the started threads exists, all the possible permutations of ``tX'' where $x$ is 1, 2 or 3 are valid outputs. Namely, all possible combinations are: \marginpar[right
text]{\color{white}\url{https://youtu.be/4U_06LuzwJY}}
\begin{itemize}
\item ``t1 t2 t3 ``
\item ``t1 t2 t3 ``
\item ``t2 t1 t3 ``
\item ``t2 t3 t1 ``
\item ``t3 t1 t2 ``
\item ``t3 t2 t1 ``
\end{itemize}
\section*{Exercise B: Concurrency}
\begin{enumerate}
\item No, as the method is \texttt{synchronized} and requires a mutually exclusive lock to be acquired to execute it, therefore only one thread at a time can execute;
\item Yes, as \textit{getCounter()} is not marked with the \texttt{synchronized} keyword;
\item Yes, as one thread may acquire the lock for \textit{incrementCounter()} while the other just released it and is executing \textit{getCounter()};
\item Yes, as the updates to the \textit{count} variable in \textit{Counter} are atomic and safe,
therefore the count will always be exact;
\item The object will acquire and release the intrinsic lock of the \textit{counter} object defined at line 17.
\end{enumerate}
\section*{Exercise C: Concurrency}
No, as the foreach loops may indeed run simultaneously. According to the Java 17 standard library documentation for \texttt{Collections.synchronizedList(...)}\footnote{\url{https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/Collections.html\#synchronizedList(java.util.List)}}, in order to obtain such access behaviour we would need to use the intrinsic lock of the list object wrapping the foreach loop with a \texttt{synchronized (integerList)} block.
\section*{Exercise D: JVM Architecture}
\begin{enumerate}
\item As invoking \texttt{javap Secret} reports:
\begin{verbatim}
Warning: File ./Secret.class does not contain class Secret
Compiled from "Login.java"\end{verbatim}
the name of the original Java file is \texttt{Login.java};
\item According to the output of \texttt{javap -c -l Secret}, specifically these lines:
\begin{verbatim}
0: ldc #55 // String Hello, try to find the username and the password [...]
71: ldc #79 // String Congratulations, now write the username and the [...]
[...]
LineNumberTable:
line 27: 0
[...]
line 41: 68
line 42: 76
[...]\end{verbatim}
the string starting with ``Hello'' is stored in tag 55 of the constant pool and is loaded at line 27. The string starting with ``Congratulations'' is stored in tag 79 of the constant pool and is loaded at line 42.
\item According to the output of \texttt{javap Secret} showing the class's interface:
\begin{verbatim}
public class Login {
public Login();
public static char transform(char);
public static boolean access(java.lang.String, java.lang.String);
public static void main(java.lang.String...);
}\end{verbatim}
there are three \texttt{public static} methods in the class.
\end{enumerate}
To aid the explanation of how we found the secret password we report the full output of
\textit{javap -c -l Secret}:
\begin{minted}{java}
public class Login {
public Login();
Code:
0: aload_0
1: invokespecial #1 // Method java/lang/Object."<init>":()V
4: return
public static char transform(char);
Code:
0: iload_0
1: bipush 97
3: isub
4: istore_1
5: iload_1
6: iconst_1
7: isub
8: bipush 26
10: irem
11: bipush 97
13: iadd
14: istore_2
15: iload_2
16: i2c
17: ireturn
public static boolean access(java.lang.String, java.lang.String);
Code:
0: ldc #7 // String tvvvvqfstuspohqbttxpse
2: astore_2
3: ldc #9 // String
5: astore_3
6: iconst_0
7: istore 4
9: iload 4
11: aload_2
12: invokevirtual #11 // Method java/lang/String.length:()I
15: if_icmpge 40
18: aload_3
19: aload_2
20: iload 4
22: invokevirtual #17 // Method java/lang/String.charAt:(I)C
25: invokestatic #21 // Method transform:(C)C
28: invokedynamic #27, 0 // InvokeDynamic #0:makeConcatWithConstants:
// (Ljava/lang/String;)Ljava/lang/String;
33: astore_3
34: iinc 4, 1
37: goto 9
40: aload_0
41: ldc #31 // String admin
43: invokevirtual #33 // Method java/lang/String.equals:(Ljava/lang/Object;)Z
46: ifeq 70
49: aload_1
50: aload_3
51: invokevirtual #37 // Method java/lang/String.toString:()Ljava/lang/String;
54: invokevirtual #33 // Method java/lang/String.equals:(Ljava/lang/Object;)Z
57: ifeq 70
60: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
63: ldc #47 // String Success!! Access granted
65: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
68: iconst_1
69: ireturn
70: iconst_0
71: ireturn
public static void main(java.lang.String...);
Code:
0: ldc #55 // String Hello, try to find the username and the [...]
2: astore_1
3: aload_1
4: invokedynamic #57, 0 // InvokeDynamic #1:makeConcatWithConstants:
// (Ljava/lang/String;)Ljava/lang/String;
9: astore_1
10: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
13: aload_1
14: iconst_0
15: anewarray #2 // class java/lang/Object
18: invokevirtual #60 // Method java/io/PrintStream.printf:(Ljava/lang/String;
// [Ljava/lang/Object;)Ljava/io/PrintStream;
21: pop
22: aload_0
23: arraylength
24: iconst_2
25: if_icmpeq 48
28: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
31: ldc #64 // String Usage:
33: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
36: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
39: ldc #66 // String java Login username password
41: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
44: iconst_m1
45: invokestatic #68 // Method java/lang/System.exit:(I)V
48: aload_0
49: iconst_0
50: aaload
51: aload_0
52: iconst_1
53: aaload
54: invokestatic #72 // Method access:(Ljava/lang/String;Ljava/lang/String;)Z
57: ifne 68
60: new #76 // class java/lang/RuntimeException
63: dup
64: invokespecial #78 // Method java/lang/RuntimeException."<init>":()V
67: athrow
68: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
71: ldc #79 // String Congratulations, now write the username and [...]
73: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
76: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
79: ldc #81 // String Provide an explanation on how you discover it.
81: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
84: goto 113
87: astore_2
88: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
91: ldc #83 // String Wrong username and/or password.
93: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
96: getstatic #41 // Field java/lang/System.out:Ljava/io/PrintStream;
99: aload_0
100: iconst_0
101: aaload
102: aload_0
103: iconst_1
104: aaload
105: invokedynamic #85, 0 // InvokeDynamic #2:makeConcatWithConstants:
// (Ljava/lang/String;Ljava/lang/String;)Ljava/lang/String;
110: invokevirtual #49 // Method java/io/PrintStream.println:(Ljava/lang/String;)V
113: return
Exception table:
from to target type
48 84 87 Class java/lang/RuntimeException
}
\end{minted}
We first understand from instructions 28 to 45 of the \textit{main} method that
the class is meant to be launched with two parameters, which are namely the
username and the password.
We see that from instructions 48 to 54 the \textit{access} static method is
invoked with the first command line argument as the first parameter and the
second command line argument as the second parameter, which are namely the
username and the password provided for login. Then the \textit{access} method
checks if its first parameter is equal to the string ``admin'' at instructions
40 to 46, returning \texttt{false} if not. Therefore we can say the the right
username is ``admin''.
We then analyze the \textit{transform} method. Instructions 0 to 4 subtract the
constant 97 (the character code of a lowercase ``a'') to the character given as
argument, storing the result in the stack variable position 1. Then,
instructions 5 to 7 subtract the constant 1 to the saved variable, instructions
7 to 10 compute the modulo 26 (\texttt{\% 26}, where 26 is the number of ASCII
lowercase letters) of the result and instructions 11 to 13 increment the final
result with the constant 97 and returns the result as a character. Instructions
14 to 17 in order store what the method computed in variable 2, loads variable 2
and returns a copy cast to type \texttt{char}. Therefore, an equivalent Java
source for the method is:
\begin{minted}{java}
public static char transform(char c) {
return (char) (((c - ((int) 'a') - 1) % 26) + ((int) 'a'));
}
\end{minted}
Instructions 0 to 37 show that a string with value ``tvvvvqfstuspohqbttxpse'' is
read character by character the method \textit{transform} is applied, forming a
new String. Given the reverse engineered \textit{transform} method and the fact
that the string is composed only of lowercase letters starting from ``b'', both
adding and subtracting ``a'' and computing a modulo 26 of each character are
operations that lead to the same character. Indeed, the only change
\textit{transform} applies to every single character is to subtract 1, or return
the preceding character of each given character. Therefore, given this, we
determine the decoded password to be the string ``suuuuperstrongpassword''.
\section*{Exercise E: Monitoring JIT}
\begin{enumerate}
\item \begin{enumerate}[(a)]
\item \texttt{-XX:-PrintCompilation}
\item \texttt{-XX:+UnlockDiagnosticVMOptions -XX:+PrintInlining}
\item \texttt{-XX:NativeMemoryTracking=summary}
\end{enumerate}
\item The output of the command \texttt{java -XX:+UnlockDiagnosticVMOptions -XX:+PrintInlining Inlining} is the following:
\begin{verbatim}
@ 17 java.lang.String::isLatin1 (19 bytes) inline
@ 27 java.lang.StringLatin1::hashCode (42 bytes) callee is too large
@ 37 java/lang/StringUTF16::hashCode (not loaded) not inlineable
@ 6 java.lang.String::coder (15 bytes) inline
@ 6 Point::<init> (15 bytes) inline
@ 1 java.lang.Object::<init> (1 bytes) inline
@ 20 Point::getY (5 bytes) inline
@ 25 Point::setX (6 bytes) inline
@ 30 Point::setY (6 bytes) inline
@ 6 Point::<init> (15 bytes) inline
@ 1 java.lang.Object::<init> (1 bytes) inline
@ 20 Point::getY (5 bytes) inline
@ 25 Point::setX (6 bytes) inline
@ 30 Point::setY (6 bytes) inline
@ 20 Point::getY (5 bytes) accessor
@ 25 Point::setX (6 bytes) accessor
@ 30 Point::setY (6 bytes) accessor\end{verbatim}
Therefore we can confirm that all methods listed were inlined while executing class \textit{Inlining}.
\end{enumerate}
\section*{Exercise F: Java Agent}
\begin{enumerate}
\item The compiled code given cannot be executed as-is as the class \textit{ch.usi.inf.ajp22.Point} contains an invalid java class file format version of 255 (where e.g. for Java 17 the correct value is 61).
\item Please find the relevant source code in folder \texttt{ExcerciseF}.
\end{enumerate}
\end{document}