87 lines
2.4 KiB
TeX
87 lines
2.4 KiB
TeX
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% vim: set ts=2 sw=2 tw=80 et:
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\documentclass[12pt]{article}
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\usepackage[margin=3cm]{geometry}
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\usepackage{xcolor}
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\usepackage{lmodern}
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\usepackage{listings}
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\title{Graded Assignment 4 -- DSA}
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\author{Claudio Maggioni}
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\setlength{\parindent}{0cm}
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% listings configuration
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\lstset{
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basicstyle=\small\ttfamily,
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frame=shadowbox,
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xleftmargin=10mm, % Move everything 10mm to the right
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framexleftmargin=10mm, % Make the frame 10mm wider to the left
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numbers=left, % Add numbers to the left of the code
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rulesepcolor=\color{black},
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columns=fullflexible,
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commentstyle=\color{gray},
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keywordstyle=\bfseries,
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keywords={,NIL,while,if,elif,else,FUNCTION,return,for,from,to,TRUE,FALSE},
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mathescape=true,
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aboveskip=2em,
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captionpos=b,
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abovecaptionskip=1em,
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belowcaptionskip=1em,
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}
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\begin{document}
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\maketitle
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\tableofcontents
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\lstlistoflistings
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\newpage
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\section{Exercise 1}
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\begin{lstlisting}[caption=Solution for exercise 1, label={lst:ex1}]
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FUNCTION BEST-PATH(G=(V,E), v, w):
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P[V(G)[0]] = NIL
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for each vertex u $\in$ V(G):
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prev_start[u] = NIL
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prev_end[u] = NIL
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prev_start[v] = START
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prev_end[w] = END
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HELP-SETUP(G, P, Adj[V(G)[0]], V(G)[0])
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s = v
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e = w
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while prev_end[s] is NIL and prev_start[e] is NIL:
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if P[s] is not NIL:
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prev_start[P[s]] = s
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s = P[s]
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if P[e] is not NIL:
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prev_end[P[e]] = e
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e = P[e]
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if prev_end[s] is not NIL:
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n = s
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else:
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n = e
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while s is not v:
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s = prev_start[s]
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prev_end[s] = P[s]
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return prev_end
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FUNCTION HELP-SETUP(G=(V,E), P, S, v):
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for each vertex u $\in$ S:
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P[u] = v
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HELP-SETUP(G, P, Adj[u] \ v, u)
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\end{lstlisting}
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The $O(n)$ setup happens between line 2 and line 14. This is mainly needed to initialize some help arrays and define an arbitrary root
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(and consequent parent relation) on the tree.
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The rest of the algorithm walks the tree from the start to the root and from the end to the root concurrently, keeping track of the path taken and stopping when an edge was traversed by both walks. Then, the path memory to the start is reversed and inserted in the path memory for the end in order to obtain a mapping to the next node in the path from $v$ to $w$. The complexity of this step is $O(dist(v,w))$, since the number of traversed edges is at most two times the distance from $v$ to $w$, and the reversing operation at the end requires at most $dist(v,w)$ steps.
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\end{document}
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