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HPC/Project0/src/fraction_summing/main.cpp

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#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include "fraction_toolbox.hpp"
using namespace std;
// read command line arguments
static void readcmdline(fraction & frac, int argc, char* argv[])
{
if (argc!=3)
{
printf("Usage: n d\n");
printf(" n numerator of fraction\n");
printf(" d denominator of fraction\n");
exit(1);
}
// read n
frac.num = atoi(argv[1]);
// read d
frac.denom = atoi(argv[2]);
}
static void test23467(int argc, char* argv[])
{
fraction frac;
readcmdline(frac, argc, argv);
cout << "#2: squared fraction" << endl;
print_fraction(square_fraction(frac));
cout << "#3: squared fraction in-place" << endl;
fraction frac2 = frac;
square_fraction_inplace(frac2);
print_fraction(frac2);
cout << "#4: fraction to double" << endl;
cout << fraction2double(frac) << endl;
cout << "#6: gcd of fraction" << endl;
cout << gcd(frac) << endl;
cout << "#7: fraction reduction in-place" << endl;
fraction frac3 = frac;
reduce_fraction_inplace(frac3);
print_fraction(frac3);
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}
static void test5()
{
int a, b;
cout << "#5: recursive gcd of two integers" << endl;
cout << "Input first number: ";
cin >> a;
cout << "Input second number: ";
cin >> b;
cout << "GCD is: " << gcd(a, b) << endl;
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}
static void test_array_functions(int n)
{
fraction* a = (fraction*) malloc(sizeof(fraction) * n);
fill_fraction_array(a, n);
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cout << "Sum of array as fraction: " << endl;
print_fraction(sum_fraction_array(a, n));
cout << "Sum of array as double (approx.): " << endl;
cout << sum_fraction_array_approx(a, n) << endl;
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// find n for which sum function breaks. Explain what is happening. n=1290
// this is the first number where the denominator overflows and thus
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// erroneoulsly becomes a negative number. The overflow is caused by the
// sum_fractions function, specifically in the multiplication between
// denominators. The approximation function doesn't overflow since fractions
// are first converted into double floating point numbers, thus never
// calling the sum_fractions functions and performing dangerous fixed size
// integer multiplications. Additionally, due to the floating point nature
// of the double type, a sum of doubles will never overflow to something
// "weird", albeit precision will be lost due to the limited number of
// significant digits and for larger and larger values the sum will
// eventually reach the value "+Infinity" due to the fixed exponent size.
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}
static void test_toolbox(int argc, char* argv[])
{
cout << "\n=============== test23467 =============== " << endl;
test23467(argc, argv);
cout << "\n================= test5 ================= " << endl;
test5();
cout << "\n========== test_array_functions ========= " << endl;
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int n = 1290;
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test_array_functions(n);
}
int main(int argc, char* argv[])
{
test_toolbox(argc, argv);
}