#include <iostream>
#include <stdio.h>
#include <stdlib.h>

#include "fraction_toolbox.hpp"

using namespace std;

// read command line arguments
static void readcmdline(fraction & frac, int argc, char* argv[])
{
    if (argc!=3)
    {
        printf("Usage: n d\n");
        printf("  n        numerator of fraction\n");
        printf("  d        denominator of fraction\n");
        exit(1);
    }

    // read n
    frac.num = atoi(argv[1]);

    // read d
    frac.denom = atoi(argv[2]);
}

static void test23467(int argc, char* argv[])
{
    fraction frac;
    readcmdline(frac, argc, argv);

    cout << "#2: squared fraction" << endl;
    print_fraction(square_fraction(frac));
    
    cout << "#3: squared fraction in-place" << endl;
    fraction frac2 = frac;
    square_fraction_inplace(frac2);
    print_fraction(frac2);

    cout << "#4: fraction to double" << endl;
    cout << fraction2double(frac) << endl;

    cout << "#6: gcd of fraction" << endl;
    cout << gcd(frac) << endl;

    cout << "#7: fraction reduction in-place" << endl;
    fraction frac3 = frac;
    reduce_fraction_inplace(frac3);
    print_fraction(frac3);
}

static void test5()
{
    int a, b;
    cout << "#5: recursive gcd of two integers" << endl;
    cout << "Input first number: ";
    cin >> a;
    cout << "Input second number: ";
    cin >> b;
    cout << "GCD is: " << gcd(a, b) << endl;
}

static void test_array_functions(int n)
{
    fraction* a = (fraction*) malloc(sizeof(fraction) * n);
    fill_fraction_array(a, n);
 
    cout << "Sum of array as fraction: " << endl;
    print_fraction(sum_fraction_array(a, n)); 

    cout << "Sum of array as double (approx.): " << endl;
    cout << sum_fraction_array_approx(a, n) << endl; 
    
    // find n for which sum function breaks. Explain what is happening. n=1290
    // this is the first number where the denominator overflows and thus
    // erroneoulsly becomes a negative number. The overflow is caused by the
    // sum_fractions function, specifically in the multiplication between
    // denominators. The approximation function doesn't overflow since fractions
    // are first converted into double floating point numbers, thus never
    // calling the sum_fractions functions and performing dangerous fixed size
    // integer multiplications. Additionally, due to the floating point nature
    // of the double type, a sum of doubles will never overflow to something
    // "weird", albeit precision will be lost due to the limited number of
    // significant digits and for larger and larger values the sum will
    // eventually reach the value "+Infinity" due to the fixed exponent size.
}

static void test_toolbox(int argc, char* argv[])
{
    cout << "\n===============  test23467  =============== " << endl;
    test23467(argc, argv);

    cout << "\n=================  test5  ================= " << endl;
    test5();

    cout << "\n==========  test_array_functions  ========= " << endl;
    int n = 1290;
    test_array_functions(n);
}

int main(int argc, char* argv[])
{
    test_toolbox(argc, argv);    
}