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Author SHA1 Message Date
Claudio Maggioni 94e42d6c4a all done except 3b 2020-04-03 11:09:45 +02:00
2 changed files with 4 additions and 2 deletions

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@ -74,7 +74,7 @@ $$f(x+h) \geq f(x) + \frac{f'(x)}{1}\cdot h + \frac{f''(x)}{2}\cdot h^2 +
\frac{f'''(x)}{6}\cdot h^3$$
$$f(x-h) \geq f(x) - \frac{f'(x)}{1}\cdot h + \frac{f''(x)}{2}\cdot h^2 -
\frac{f'''(x)}{6}\cdot h^3 $$
\frac{f'''(x)}{6}\cdot h^3$$
Then, we can derive that:
@ -87,7 +87,9 @@ $$
So:
$$ \left|f'(x) - \frac{f(x + h) - f(x - h)}{2h}\right| \leq \left|f'(x) - \left(f'(x) + \frac{h^2f'''(x)}{6}\right)
\right| = \frac{h^2|f'''(x)|}{6}$$
\right| = \frac{h^2|f'''(x)|}{6}
\Rightarrow
C = \frac{f'''(x)}{6}$$
\section*{Question 4}
\subsection*{Point a)}