commit 24600885b9a049ce13de506bd255ea04e91dda1b
Author: github-classroom[bot] <66690702+github-classroom[bot]@users.noreply.github.com>
Date:   Mon Nov 13 12:47:53 2023 +0000

    Initial commit

diff --git a/.gitattributes b/.gitattributes
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+++ b/.gitattributes
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+# Auto detect text files and perform LF normalization
+* text=auto
diff --git a/README.md b/README.md
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+# Project 02 - Python test generator
+
+### About the Project
+
+This project has the goal of writing a search based automated test generator for Python.
+It is part of the Knowledge Search & Extraction - 2023 course from the Università della Svizzera italiana.
+
+In this repository, you can find the following files:
+- benchmark folder: which contains the benchmark of functions under test to be instrumented
+
+Note: Feel free to modify this file according to the project's necessities.
+
+
+ 
diff --git a/benchmark/anagram_check.py b/benchmark/anagram_check.py
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+++ b/benchmark/anagram_check.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/anagram_check.py
+
+# function to check if two strings are
+# anagram or not  
+def anagram_check(s1: str, s2: str) -> bool:
+    if len(s1) == 1 and len(s2) == 1:
+        return s1 == s2
+    if len(s1) != len(s2):
+        return False
+
+    # the sorted strings are checked
+    if ''.join(sorted(s1)) == ''.join(sorted(s2)):
+        return True
+    else:
+        return False
diff --git a/benchmark/caesar_cipher.py b/benchmark/caesar_cipher.py
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+++ b/benchmark/caesar_cipher.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/caesar_cipher.py
+
+
+def encrypt(strng: str, key: int) -> str:
+    assert 0 < key <= 94
+    encrypted = ''
+    for x in strng:
+        indx = (ord(x) + key) % 256
+        if indx > 126:
+            indx = indx - 95
+        encrypted = encrypted + chr(indx)
+    return encrypted
+
+
+def decrypt(strng: str, key: int) -> str:
+    assert 0 < key <= 94
+    decrypted = ''
+    for x in strng:
+        indx = (ord(x) - key) % 256
+        if indx < 32:
+            indx = indx + 95
+        decrypted = decrypted + chr(indx)
+    return decrypted
+
+
diff --git a/benchmark/check_armstrong.py b/benchmark/check_armstrong.py
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+++ b/benchmark/check_armstrong.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/check_armstrong.py
+
+def check_armstrong(n: int) -> bool:
+	assert n >= 0
+	if n == 0 or n == 1:
+		return True
+	if n <= 150:
+		return False
+	t = n
+	sum = 0
+	while t != 0:
+		r = t % 10
+		sum = sum + (r * r * r)
+		t = t // 10
+	if sum == n:
+		return True
+	else:
+		return False
diff --git a/benchmark/common_divisor_count.py b/benchmark/common_divisor_count.py
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+++ b/benchmark/common_divisor_count.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/common_divisor_count.py
+
+"""
+The function takes two integers as input and return the number of common divisors of
+that pair
+"""
+
+
+def cd_count(a: int, b: int) -> int:
+    if a == 0 or b == 0:
+        return 2
+    a = (-1 * a if a < 0 else a)
+    b = (-1 * b if b < 0 else b)
+
+    result = 0
+    while a != 0:
+        c = a
+        a = b % a
+        b = c
+
+    for i in range(1, int((b ** 0.5) + 1)):
+        if b % i == 0:
+            if int(b / i) == i:
+                result = result + 1
+            else:
+                result = result + 2
+    return result
diff --git a/benchmark/exponentiation.py b/benchmark/exponentiation.py
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+++ b/benchmark/exponentiation.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/exponentiation.py
+
+def exponentiation(baseNumber: int, power: int) -> float:
+    assert not (baseNumber == 0 or power <= 0)
+
+    answer = None
+    
+    if power > 1:
+        halfAnswer = exponentiation(baseNumber, power//2)
+        answer = halfAnswer * halfAnswer
+        
+        if power%2 == 1:
+            answer *= baseNumber
+    
+    elif power == 1:
+        answer = baseNumber
+    
+    elif power == 0:
+        answer = 1
+    
+    else: # negative power
+        answer = 1 / exponentiation(baseNumber, abs(power))
+    
+    return answer
diff --git a/benchmark/gcd.py b/benchmark/gcd.py
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+++ b/benchmark/gcd.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/common_divisor_count.py
+
+def gcd(a: int, b: int) -> int:
+    assert a > 0 and b > 0
+    if a == 1 or b == 1:
+        return 1
+    if a == b:
+        return a
+    if b > a:
+        a, b = b, a
+    while b != 0:
+        temp = b
+        b = a % b
+        a = temp
+    return a
diff --git a/benchmark/longest_substring.py b/benchmark/longest_substring.py
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+++ b/benchmark/longest_substring.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/longest_substring.py
+
+# Create an algorithm that prints the longest substring of s in which
+# the letters occur in alphabetical order. For example, if
+# s = 'azcbobobegghakl', then your program should print:
+# Longest substring in alphabetical order is: beggh
+
+# In the case of ties, print the first substring.
+# For example, if s = 'abcbcd', then your program should print:
+# Longest substring in alphabetical order is: abc
+
+
+def longest_sorted_substr(s: str) -> str:
+    count = 0
+    max_count = 0
+    end_position = 0
+    for char in range(len(s) - 1):
+        if (s[char] <= s[char + 1]):
+            count += 1
+            if count > max_count:
+                max_count = count
+                end_position = char + 1
+        else:
+            count = 0
+    start_position = end_position - max_count
+    return s[start_position:end_position+1]
+
+
diff --git a/benchmark/rabin_karp.py b/benchmark/rabin_karp.py
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+++ b/benchmark/rabin_karp.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/rabin_karp.py
+
+
+# Rabin Karp Algorithm in python using hash values
+
+
+def rabin_karp_search(pat: str, txt: str) -> list:
+    assert len(pat) <= len(txt)
+
+    # d is the number of characters in input alphabet
+    d = 2560
+    q = 101
+
+    M = len(pat)
+    N = len(txt)
+    i = 0
+    j = 0
+
+    p = 0
+    t = 0
+    h = 1
+
+    for i in range(M - 1):
+        h = (h * d) % q
+
+    for i in range(M):
+        p = (d * p + ord(pat[i])) % q
+        t = (d * t + ord(txt[i])) % q
+
+    found_at_index = []
+    for i in range(N - M + 1):
+        if p == t:
+            for j in range(M):
+                if txt[i + j] != pat[j]:
+                    break
+
+            j += 1
+            if j == M:
+                found_at_index.append(i)
+
+        if i < N - M:
+            t = (d * (t - ord(txt[i]) * h) + ord(txt[i + M])) % q
+            if t < 0:
+                t = t + q
+
+    return found_at_index
diff --git a/benchmark/railfence_cipher.py b/benchmark/railfence_cipher.py
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+++ b/benchmark/railfence_cipher.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/railfence_cipher.py
+
+
+def railencrypt(st: str, k: int) -> str:
+    assert k > 1
+    c = 0
+    x = 0
+    m =[[0] * (len(st)) for i in range(k)]
+    for r in range(len(st)):
+        m[c][r] = ord(st[r])
+        if x == 0:
+            if c == (k-1):
+                x = 1
+                c -= 1
+            else:
+                c += 1
+        else:
+            if c == 0:
+                x = 0
+                c += 1
+            else:    
+                c -= 1
+           
+    result = [] 
+    for i in range(k): 
+        for j in range(len(st)): 
+            if m[i][j] != 0: 
+                    result.append(chr(m[i][j]))
+    return ''.join(result)
+
+
+def raildecrypt(st: str, k: int) -> str:
+    assert k > 1
+    c , x = 0 , 0
+    m =[[0] * (len(st)) for i in range(k)]
+    for r in range(len(st)):
+        m[c][r] = 1
+        if x == 0:
+            if c == (k-1):
+                x = 1
+                c -= 1
+            else:
+                c += 1
+        else:
+            if c == 0:
+                x = 0
+                c += 1
+            else:    
+                c -= 1
+    result = []
+    c , x = 0 , 0
+    for i in range(k): 
+        for j in range(len(st)): 
+            if m[i][j] == 1:
+                m[i][j] = ord(st[x])
+                x += 1
+    for r in range(len(st)):
+        if m[c][r] != 0:
+            result.append(chr(m[c][r]))
+        if x == 0:
+            if c == (k-1):
+                x = 1
+                c -= 1
+            else:
+                c += 1
+        else:
+            if c == 0:
+                x = 0
+                c += 1
+            else:    
+                c -= 1
+    return ''.join(result)
+
diff --git a/benchmark/zellers_birthday.py b/benchmark/zellers_birthday.py
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+++ b/benchmark/zellers_birthday.py
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+# Based on https://github.com/AllAlgorithms, python/algorithms/math/zellers_birthday.py
+
+
+def zeller(d: int, m: int, y: int) -> str:
+    assert abs(d) >= 1
+    assert abs(m) >= 1
+    assert 0 <= abs(y) <= 99 or 1000 <= abs(y) <= 3000
+
+    d = abs(d)
+    m = abs(m)
+    y = abs(y)
+    if d > 31:
+        d = d % 31 + 1
+    if m > 12:
+        m = m % 12 + 1
+    if y < 100 and y < 23:
+        y = 2000 + y
+    if y < 100 and y >= 23:
+        y = 1900 + y
+
+    days = {
+        '0': 'Sunday',
+        '1': 'Monday',
+        '2': 'Tuesday',
+        '3': 'Wednesday',
+        '4': 'Thursday',
+        '5': 'Friday',
+        '6': 'Saturday'
+    }
+
+    # m = int(bday[0] + bday[1])
+    # d = int(bday[3] + bday[4])
+    # y = int(bday[6] + bday[7] + bday[8] + bday[9])
+
+    if m <= 2:
+        y = y - 1
+        m = m + 12
+    c = int(str(y)[:2])
+    k = int(str(y)[2:])
+
+    t = int(2.6 * m - 5.39)
+    u = int(c / 4)
+    v = int(k / 4)
+    x = d + k
+    z = t + u + v + x
+    w = z - (2 * c)
+
+    f = round(w % 7)
+
+    for i in days:
+        if f == int(i):
+            return days[i]