GA2 done. Selection sort added

This commit is contained in:
Claudio Maggioni 2019-03-25 15:21:57 +01:00
parent 13030cc6bc
commit 8301104864
5 changed files with 138 additions and 38 deletions

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@ -32,14 +32,131 @@
\lstlistoflistings \lstlistoflistings
\newpage \newpage
\section{Exercise 1}
\subsection{Mergesort}
\begin{verbatim}
[5, 6, 12, 8, 4, 10, 3, 12, 11, 1]
[5, 6, 12, 8, 4] [10, 3, 12, 11, 1]
[5, 6, 12, 8, 4]
[5, 6], [12, 8, 4]
[5, 6]
[5], [6]
[5]
[6]
[5, 6]
[12, 8, 4]
[12] [8, 4]
[12]
[8, 4]
[8], [4]
[8]
[4]
[4, 8]
[4, 8, 12]
[4, 5, 6, 8, 12]
[10, 3, 12, 11, 1]
[10, 3], [12, 11, 1]
[10], [3]
[10]
[3]
[3, 10]
[12, 11, 1]
[12], [11, 1]
[12]
[11, 1]
[11], [1]
[11]
[1]
[1, 11]
[1, 11, 12]
[1, 3, 10, 11, 12]
[1, 3, 4, 5, 6, 8, 10, 11, 12, 12]
\end{verbatim}
\subsection{Selection sort}
\begin{verbatim}
[4, 6, 12, 8, 5, 10, 3, 12, 11, 1]
[3, 6, 12, 8, 5, 10, 4, 12, 11, 1]
[1, 6, 12, 8, 5, 10, 4, 12, 11, 3]
[1, 5, 12, 8, 6, 10, 4, 12, 11, 3]
[1, 4, 12, 8, 6, 10, 5, 12, 11, 3]
[1, 3, 12, 8, 6, 10, 5, 12, 11, 4]
[1, 3, 8, 12, 6, 10, 5, 12, 11, 4]
[1, 3, 6, 12, 8, 10, 5, 12, 11, 4]
[1, 3, 5, 12, 8, 10, 6, 12, 11, 4]
[1, 3, 4, 12, 8, 10, 6, 12, 11, 5]
[1, 3, 4, 8, 12, 10, 6, 12, 11, 5]
[1, 3, 4, 6, 12, 10, 8, 12, 11, 5]
[1, 3, 4, 5, 12, 10, 8, 12, 11, 6]
[1, 3, 4, 5, 10, 12, 8, 12, 11, 6]
[1, 3, 4, 5, 8, 12, 10, 12, 11, 6]
[1, 3, 4, 5, 6, 12, 10, 12, 11, 8]
[1, 3, 4, 5, 6, 10, 12, 12, 11, 8]
[1, 3, 4, 5, 6, 8, 12, 12, 11, 10]
[1, 3, 4, 5, 6, 8, 11, 12, 12, 10]
[1, 3, 4, 5, 6, 8, 10, 12, 12, 11]
[1, 3, 4, 5, 6, 8, 10, 11, 12, 12]
[1, 3, 4, 5, 6, 8, 10, 11, 12, 12]
\end{verbatim}
\subsection{Quicksort}
\begin{verbatim}
[5, 6, 12, 8, 4, 10, 3, 12, 11, 1]
[5, 6, 3, 1, 4] 8 [12, 12, 11, 10]
[] 1 [6, 3, 4, 5]
[] 3 [5, 4, 6]
[5, 4] 6 []
[4] 5 []
[4] 5 []
[4, 5] 6 []
[] 3 [4, 5, 6]
[] 1 [3, 4, 5, 6]
[10] 11 [12, 12]
[12] 12 []
[12] 12 []
[10] 11 [12, 12]
[1, 3, 4, 5, 6] 8 [10, 11, 12, 12]
[1, 3, 4, 5, 6, 8, 10, 11, 12, 12]
\end{verbatim}
\subsection{Insertion sort}
\begin{verbatim}
[5, 6, 12, 8, 4, 10, 3, 12, 11, 1]
[5, 6, 8, 12, 4, 10, 3, 12, 11, 1]
[5, 6, 8, 4, 12, 10, 3, 12, 11, 1]
[5, 6, 4, 8, 12, 10, 3, 12, 11, 1]
[5, 4, 6, 8, 12, 10, 3, 12, 11, 1]
[4, 5, 6, 8, 12, 10, 3, 12, 11, 1]
[4, 5, 6, 8, 10, 12, 3, 12, 11, 1]
[4, 5, 6, 8, 10, 3, 12, 12, 11, 1]
[4, 5, 6, 8, 3, 10, 12, 12, 11, 1]
[4, 5, 6, 3, 8, 10, 12, 12, 11, 1]
[4, 5, 3, 6, 8, 10, 12, 12, 11, 1]
[4, 3, 5, 6, 8, 10, 12, 12, 11, 1]
[3, 4, 5, 6, 8, 10, 12, 12, 11, 1]
[3, 4, 5, 6, 8, 10, 12, 11, 12, 1]
[3, 4, 5, 6, 8, 10, 11, 12, 12, 1]
[3, 4, 5, 6, 8, 10, 11, 12, 1, 12]
[3, 4, 5, 6, 8, 10, 11, 1, 12, 12]
[3, 4, 5, 6, 8, 10, 1, 11, 12, 12]
[3, 4, 5, 6, 8, 1, 10, 11, 12, 12]
[3, 4, 5, 6, 1, 8, 10, 11, 12, 12]
[3, 4, 5, 1, 6, 8, 10, 11, 12, 12]
[3, 4, 1, 5, 6, 8, 10, 11, 12, 12]
[3, 1, 4, 5, 6, 8, 10, 11, 12, 12]
[1, 3, 4, 5, 6, 8, 10, 11, 12, 12]
\end{verbatim}
\section{Exercise 2} \section{Exercise 2}
\subsection{Exercise a} \subsection{Exercise a}
The pseudocode for \textit{Sum of two} can be found in listing \ref{lst:sum2}. The pseudocode for \textit{Sum of two} can be found in listing \ref{lst:sum2}.
The total cost of this algorithm in the worst case is the sum of the worst case The total cost of this algorithm in the worst case is the sum of the worst case
of mergesort ($O(n log(n))$) and the cost of the worst case in the partition of mergesort ($O(n log(n))$) and the cost of the worst case in the partition
done afterwards (which is equivalent to not finding the sum, i.e. $2 n = done afterwards (which is equivalent to not finding a sum close to the median,
O(n)$). Therefore, the total cost is $\theta(n log(n))$. i.e. $2 n = O(n)$). Therefore, the total cost is $\theta(n log(n))$.
\begin{lstlisting}[caption=Sum of two in pseudocode, label={lst:sum2}] \begin{lstlisting}[caption=Sum of two in pseudocode, label={lst:sum2}]
FUNCTION SUM-OF-TWO(A, s): FUNCTION SUM-OF-TWO(A, s):

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@ -8,11 +8,10 @@ def insertionsort(A):
# insert the next element in the right place in the first elements # insert the next element in the right place in the first elements
# continue until the array is done # continue until the array is done
for j in range(1,len(A)): for j in range(1,len(A)):
print(A)
print(A)
i = j - 1 i = j - 1
# while swapping is necessary or at the end of array # while swapping is necessary or at the end of array
while i >= 0 and A[i+1] < A[i]: while i >= 0 and A[i+1] < A[i]:
print(A)
# Swap A[i] and A[j] # Swap A[i] and A[j]
A[i+1], A[i] = A[i], A[i+1] A[i+1], A[i] = A[i], A[i+1]
i = i - 1 i = i - 1

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@ -1,34 +0,0 @@
#!/usr/bin/env python3
# vim: set ts=4 sw=4 et tw=80:
import sys
import math
def find(A,x):
for a in A:
if a == x:
return True
return False
def merge(A,B):
X = []
for a in A:
if not find(X, a):
X.append(a)
for b in B:
if not find(X, b):
X.append(b)
return X
def mergesort(A):
l = len(A)
if l < 2:
return A
else:
lh = len(A) // 2
h1 = mergesort(A[:lh])
h2 = mergesort(A[lh:])
return merge(h1,h2)
args = [int(x) for x in sys.argv[1:]]
print(mergesort(args))

18
selection.py Executable file
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@ -0,0 +1,18 @@
#!/usr/bin/env python3
import sys
def selectionsort(A):
if len(A) < 2:
return A
for i in range(len(A)):
for j in range(i + 1, len(A)):
if A[i] > A[j]:
A[i], A[j] = A[j], A[i]
print(A)
return A
if __name__ == "__main__":
args = [int(x) for x in sys.argv[1:]]
print(selectionsort(args))